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写Python写爬虫,访问一下ajax api,写着非法访问,请问有什么解决思路吗?

这里写着非法请求来源,是不是说明传递的参数和cookie这些都成功了,
只是被服务器拦截了?
还有遇到这种问题,不用selenium,有什么解决思路吗?
盼着大家多多少少说点,一个关键词也行,我自己去查查学习了。

QQ拼音截图20200527151317.png


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这里写着非法请求来源,是不是说明传递的参数和cookie这些都成功了

非法请求直接就意味着你的请求传递的东西不对.
再直接点告诉你, 直通车是要在data里传一个token的.
自己抓包看看, 做爬虫第一步是要学会抓包, 照着请求包里的参数去做.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
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